linux - Call another shell script with argument which contains whitespce -


script a:

#!/bin/bash . foo.sh args="a \"b c\" d" ./foo.sh $args

script foo:

#!/bin/bash  echo "$1" echo "$2" echo "$3" echo "$4"

after executing script a, got following result:

a

"b

c"

d

my expected result is:

a

b c

d

could tell me reason, , how change expected result, in advance.

to store multiple arguments white-spaces better use shell arrays:

args=(a "b c" d)

and call script as

./foo.sh "${args[@]}"

this print:

a b c d

-

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