java - I add two numbers with the same way but get different values -


the following code , extremely confused results get.

byte[] bytes = new byte[2]; bytes[0] = (byte)0xe6; bytes[1] = (byte)0x1b; int high = (bytes[1] & 0xff)*256; int low = bytes[0] & 0xff; double j = high + low; double = (bytes[1] & 0xff)*256 + bytes[0] & 0xff; system.out.println(bytes[1] & 0xff); system.out.println(bytes[0] & 0xff); system.out.println((bytes[1] & 0xff)*256); system.out.println(i); system.out.println(j);

logically, i , j same result quite amazing.

results:

27 230 6912 230.0 7142.0

i , j should same isn't. don't know reason. there explanation this?

they aren't equivalent; in java, the bitwise & operator has lower precedence + operator. i being defined ((bytes[1] & 0xff)*256 + bytes[0])& 0xff, evaluates 230, instead of intended 7142. replacing line i = (bytes[1] & 0xff)*256 + (bytes[0] & 0xff); need do.


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