php - Display value for dropdown populated from database (SQL Server) -


i trying display saved value dynamic dropdown populated database. code below : 

<?php $server = "xxx"; $options = array(  "uid" => "xxx",  "pwd" => "xxx",  "database" => "xxx"); $conn = sqlsrv_connect($server, $options); if ($conn === false) die("<pre>".print_r(sqlsrv_errors(), true)); echo " ";  $myquery="select department change_details id='2137'";    $fetched=sqlsrv_query($conn,$myquery) ;  if( $fetched === false ) { die( print_r( sqlsrv_errors(), true ));}     while($res=sqlsrv_fetch_array($fetched,sqlsrv_fetch_assoc))     {         $department=$res['department'];     }  ?>  <div class="container"> <!-- department -->     <div class="form-inline clearfix">         <label class="col-md-5">department initiating request</label>             <label name="department"></label>                 <div class="col-md-5">                             <?php                             echo "<select name= 'department' class='form-control selectpicker' onchange='getstate(this.value)' required>";                             echo '<option value="$department">'.'--please select department--'.'</option>';                             $sql = "select id,name departments";                             $query = sqlsrv_query($conn,$sql);                             $query_display = sqlsrv_query($conn,$sql);                             while($row=sqlsrv_fetch_array($query_display,sqlsrv_fetch_assoc)){                             echo "<option value='". $row['name']."'>".$row['name']. '</option>';                             }                             echo "</select>";                         ?>                 </div>     </div> </div><br/>

what working : dropdown being populated perfectly, , value saved database.

what need : want display saved value database , dropdown user edit field again. appreciate :)

you need current user selected value, when iterating on result set can this:

while($row=sqlsrv_fetch_array($query_display,sqlsrv_fetch_assoc)){     if ($department == $row['name']) {         echo "<option selected='selected' value='". $row['name']."'>".$row['name']. '</option>';         continue;     }      echo "<option value='". $row['name']."'>".$row['name']. '</option>'; }

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