linux - bash scripting language print a list of numbers using a loop -

i want print in text file (numberlist.txt), using bash, numbers 000000 999999, 1 number in each line. example:

000000 000001 000002  ...  999999 

this code: (when run nothing happens)

#!/bin/bash  cont=0 max_num=1000000 file_name=numberlist.txt  #while counter cont lower max_num (-lt, “lower #than”) loop executed until [ $cont -lt $max_num ];      printf "%000002d\n" $cont > $file_name      #cont= cont + 1      let cont+=1 done 

what doing wrong?

instead of opening , closing file million times, once redirecting output of the loop instead of printf:

#!/bin/bash  cont=0 max_num=1000000 file_name=numberlist.txt  while [ $cont -lt $max_num ];      printf "%06d\n" $cont       #cont= cont + 1      let cont++ done > $file_name