C++ How do I print elements of an array but leave out repeats? -

my assignment have user type in how many elements in array enter integer number put in array. have sort through array , find largest number , print out elements of array if there repeat print number 1 time. have print out number of times each element in array occurs. example if user types in there 5 elements enters 2, 1, 2, -3, 2 should print -3 1 count, 1 1 count, , 2 3 count. far have print out elements , delete repeats cant print out correct number of occurrences each element. code far.

            void findrepeats(int numbers[], int num)             {                 int instances = 0;                  cout << "number" << " " << "occurrences" << endl;                 (int = 0; < num; i++)                 {                     bool matching = false;                     instances = 1;                     (int j = 0; (j < i); j++)                     {                         if (numbers[i] == numbers[j])                         {                             instances++;                             matching = true;                          }                      }                     if (!matching)                          cout << numbers[i] << "      " << instances << endl;                  }             } 

right saying number occur 1 time

one approach take, sort numbers first, before deciding how many duplicates there are. way, easier avoid printing results same number more once, , won't have loop through entire array each number.

void findrepeats(int numbers[], int num);  int main(){    int array[] = {2, 1, 2, -3, 2};   findrepeats(array,5);  }  void findrepeats(int numbers[], int num) {      //sort array first     std::sort(numbers, numbers + num);      int last = numbers[0];     int count = 0;     cout << "number of occurrences\n";      (int = 0; < num; i++) {         if (last == numbers[i]) {             ++count;         } else {             cout << last << "      " << count << '\n';             count = 1;         }         last = numbers[i];     }      if (count > 0) {         cout << last << "      " << count << '\n';     }  } 

prints:

number of occurrences -3      1 1      1 2      3